Program to find armstrong number between 1 to 1000

 Number of n digits which are equal to sum of nth power of digit.

Program

for i in range(1,1000):

    num=i

    n=len(str(i))

    sum1=0

    i=str(i)

    for digit in i:

         sum1=sum1+int(digit)**n

    if sum1==num:

         print(num)

Output

1

2

3

4

5

6

7

8

9

153

370

371

407

Example 

To check 153 is armstrong number or not.

153

Length of number 153 is 3

=1^3+5^3+3^3

=1+125+27

=153

So that sum 153 equal to the original number 153 that number is armstrong number.