r=[2,1,0,3] for i in r: r[s]=0 print(r) output first r[2]=0 so list [2,1,0,3] next r[1]=0 so list[2,0,0,3] nextr[0]=0 so list [0,0,0,3] next r[3]=0 so list[0,0,0,0] [0,0,0,0]Q2.Program to find common b/w three sorted list.
def fc(a,b,c): n=len(a) m=len(b) k=len(c) for i in range(0,n): for j in range(0,m): if(a[i]==b[j]): for k in range(0,k): if(a[i]==c[k]): print(a[i]) a=[1,2,3] b=[2,3,4] c=[2,3,5] fc(a,b,c)Q3.what is the out of code
r=[1,2,2,1] for i in r: r[s]=1 print(r) output [1,1,1,1]Q4.Program to find subarray from array.
def suba(a): n=len(a) for i in range(0,n+1): for j in range(i,n+1): for k in range(i,j): print(a[k], end="") print() a=[1,2,3,4] suba(a)Q5. what is the output of code
r=[1,2,3,4] for i in r: r[i]=0 print(r) output [0, 0, 3, 0]
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